The kinetic energies of two similar cars A and B are 100 J and 225J respectively on applying brakes Car A stops after 1000 m and Car B stops after 1500 m if Fa and Fb are the forces applied by the brakes on cars A and B respectively then the ratio of Fa to Fb is- NEET 2025 PYQ

NEET 2025 Physics: Work-Energy Theorem

Q. The kinetic energies of two similar cars A and B are 100 J and 225 J respectively. On applying brakes, car A stops after 1000 m and car B stops after 1500 m. If FA and FB are the forces applied by the brakes on cars A and B respectively, then the ratio of FA to FB is:

1. 1/3

2. 1/2

3. 3/2

4. 2/3

Explanation:
Using the Work-Energy Theorem:
FA × SA = KA, FB × SB = KB
FA/FB = (KA/KB) × (SB/SA) = (100/225) × (1500/1000) = 2/3

This NEET 2025 Physics MCQ strengthens your concepts in work-energy applications. Such problems help you solve braking and motion-based questions with speed and confidence. Practicing PYQs ensures better results in NEET exams.