A ball is projected vertically upwards from the ground.It takes 4s to reach appoint P still moving upwards if it takes 10s further to reach to ground then height of point P is

Q3. A ball is projected vertically upwards from the ground. It takes 4 s to reach a point P still moving upwards. If it takes 10 s further to reach to ground, then height of point P is

Using symmetry and equations of motion: Total time = 14s, time from top to P = 10s → Time to reach top = 4s. So time from P to top = 0s. Hence height of P = 0.5 × g × t² = 0.5 × 10 × 4² = 400 m.