Question: The mole weight of NaCl determined by studying freezing point depression of its 0.5% aqueous solution is 30. The apparent degree dissociation of NaCl is
✅ Correct Answer: 0.95
Explanation: The degree of dissociation is determined based on the colligative property – freezing point depression. Given molar mass is 30 g/mol instead of expected 58.5 g/mol, indicating nearly full dissociation. Hence, apparent degree of dissociation is approximately 0.95.
Explanation: The degree of dissociation is determined based on the colligative property – freezing point depression. Given molar mass is 30 g/mol instead of expected 58.5 g/mol, indicating nearly full dissociation. Hence, apparent degree of dissociation is approximately 0.95.
