A particle starts from rest with constant acceleration and its velocity after t second is v the displacement of the particle in last two second of its motion is equal to

A particle starts from rest with constant acceleration and its velocity after t seconds is v. The displacement of the particle in last two seconds of its motion is equal to:

1. (v / t) × (t – 1)

2. (2v / t) × (t + 1)

3. (2v / t) × (t – 1)

4. (2v / t) × (t – 2)

Explanation:
Displacement in the last 2 seconds = s_t – s_t-2. Using s = vt – ½at² and v = at, final displacement becomes
⇒ (2v / t) × (t – 2)