A proton and a duetron (q=+e , m=2.0u) having same kinetic energies enter a regionof uniform magnetic field B moving perpendicular to B. The ratio of the radius Rd of deutron path to radius of proton Rp is
A) 1:1
B) 1:√2
C) √2:1
D) 1:2
✅ Explanation: In Uniform Magnetic field, radius of the circular path is given by R = mv/qB
=√2mKE/qB
R~√m/q (KE is same)
Rd/Rp = √Md × Qp / √Mp × Qd
Rd/Rp = √2 : 1
Here, for NaCl: n = 2 (Na⁺ and Cl⁻), and given values lead to α ≈ 0.95.
i = 1 + α(n - 1)Here, for NaCl: n = 2 (Na⁺ and Cl⁻), and given values lead to α ≈ 0.95.
